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{"version":3,"file":"can2C13-nWX5DKU5.js","sources":["../../src/exercices/can/2e/can2C13.js"],"sourcesContent":["import { choice } from '../../../lib/outils/arrayOutils'\nimport { ecritureParentheseSiNegatif } from '../../../lib/outils/ecritures.js'\nimport { miseEnEvidence } from '../../../lib/outils/embellissements'\nimport Exercice from '../../Exercice.js'\nimport { randint } from '../../../modules/outils.js'\nexport const titre = 'Calculer avec  des puissances'\nexport const interactifReady = true\nexport const interactifType = 'mathLive'\nexport const amcReady = true\nexport const amcType = 'AMCNum'\nexport const dateDePublication = '15/09/2022' // La date de publication initiale au format 'jj/mm/aaaa' pour affichage temporaire d'un tag\n\n/**\n * Modèle d'exercice très simple pour la course aux nombres\n * @author Gille Mora\n *\n*/\n\nexport const uuid = 'b31eb'\nexport const ref = 'can2C13'\nexport default function CalculPuissancesOperation () {\n  Exercice.call(this)\n  this.typeExercice = 'simple'\n  this.nbQuestions = 1\n  this.tailleDiaporama = 2\n  this.formatChampTexte = 'largeur15 inline'\n  this.nouvelleVersion = function () {\n    let a, b, n, p, s\n    switch (choice(['a', 'b', 'c', 'd', 'e'])) { //, 'b', 'c', 'd', 'e', 'f'\n      case 'a':\n        a = randint(-9, 9, [0, 1, -1])\n        n = randint(-9, 9, [0, 1, -1])\n        p = randint(-9, 9, [0, 1, -1])\n        s = n + p\n        this.question = `Écrire sous la forme $a^n$ où $a$ et $n$ sont des entiers relatifs. <br>\n        $${ecritureParentheseSiNegatif(a)}^{${n}}\\\\times ${ecritureParentheseSiNegatif(a)}^{${p}}$`\n        this.correction = `On utilise la formule $a^n\\\\times a^m=a^{n+m}$ avec $a=${a}$, $n=${n}$ et $p=${p}$.<br>\n        $${ecritureParentheseSiNegatif(a)}^{${n}}\\\\times ${ecritureParentheseSiNegatif(a)}^{${p}}=${ecritureParentheseSiNegatif(a)}^{${n}+${ecritureParentheseSiNegatif(p)}}=${miseEnEvidence(`${ecritureParentheseSiNegatif(a)}^{${n + p}}`)}$\n        `\n        this.reponse = `${ecritureParentheseSiNegatif(a)}^{${n + p}}`\n\n        break\n      case 'b':\n        a = randint(-9, 9, [0, 1, -1])\n        b = randint(-9, 9, [0, 1, -1])\n        n = randint(-9, 9, [0, 1, -1])\n        p = a * b\n        this.question = `Écrire sous la forme $a^n$ où $a$ et $n$ sont des entiers relatifs. <br>\n        $${ecritureParentheseSiNegatif(a)}^{${n}}\\\\times ${ecritureParentheseSiNegatif(b)}^{${n}}$`\n        this.correction = `On utilise la formule $a^n\\\\times b^n=(a\\\\times b)^{n}$\n        avec $a=${a}$,  $b=${b}$ et $n=${n}$.<br>\n        $${ecritureParentheseSiNegatif(a)}^{${n}}\\\\times ${ecritureParentheseSiNegatif(b)}^{${n}}=(${ecritureParentheseSiNegatif(a)}\\\\times ${ecritureParentheseSiNegatif(b)})^{${n}}=${miseEnEvidence(`${ecritureParentheseSiNegatif(p)}^{${n}}`)}$\n        `\n        this.reponse = `${ecritureParentheseSiNegatif(p)}^{${n}}`\n        break\n\n      case 'c':\n        a = randint(-9, 9, [0, 1, -1])\n        p = randint(-9, 9, [0, 1])\n        n = randint(-9, 9, [0, 1, -1])\n        s = n * p\n        this.question = `Écrire sous la forme $a^n$ où $a$ et $n$ sont des entiers relatifs. <br>\n        $\\\\left(${ecritureParentheseSiNegatif(a)}^{${n}}\\\\right)^{${p}}$`\n        this.correction = `On utilise la formule $\\\\left(a^n\\\\right)^p=a^{n\\\\times p}$\n        avec $a=${a}$,  $n=${n}$ et $p=${p}$.<br>\n        $\\\\left(${ecritureParentheseSiNegatif(a)}^{${n}}\\\\right)^{${p}}=${ecritureParentheseSiNegatif(a)}^{${n}\\\\times ${ecritureParentheseSiNegatif(p)}}=${miseEnEvidence(`${ecritureParentheseSiNegatif(a)}^{${n * p}}`)}$\n        `\n        this.reponse = `${ecritureParentheseSiNegatif(a)}^{${s}}`\n        break\n\n      case 'd':\n        a = randint(-9, 9, [0, 1, -1])\n        p = randint(-9, 9, [0, 1])\n        n = randint(-9, 9, [0, 1, -1])\n        s = n - p\n        this.question = `Écrire sous la forme $a^n$ où $a$ et $n$ sont des entiers relatifs. <br>\n        $\\\\dfrac{${ecritureParentheseSiNegatif(a)}^{${n}}}{${ecritureParentheseSiNegatif(a)}^{${p}}}$`\n        this.correction = `On utilise la formule $\\\\dfrac{a^n}{a^p}=a^{n-p}$ avec $a=${a}$,  $n=${n}$ et $p=${p}$.<br>\n        $\\\\dfrac{${ecritureParentheseSiNegatif(a)}^{${n}}}{${ecritureParentheseSiNegatif(a)}^{${p}}}=${ecritureParentheseSiNegatif(a)}^{${n}- ${ecritureParentheseSiNegatif(p)}}=${miseEnEvidence(`${ecritureParentheseSiNegatif(a)}^{${n - p}}`)}$\n        `\n        this.reponse = `${ecritureParentheseSiNegatif(a)}^{${s}}`\n        break\n      case 'e':\n\n        b = randint(2, 6, [0, 1, -1])\n        a = choice([2, 3, 4, 5, 6, 7]) * b\n        n = randint(-9, 9, [0, 1, -1])\n        s = a / b\n        this.question = `Écrire sous la forme $a^n$ où $a$ et $n$ sont des entiers relatifs. <br>\n        $\\\\dfrac{${ecritureParentheseSiNegatif(a)}^{${n}}}{${ecritureParentheseSiNegatif(b)}^{${n}}}$`\n        this.correction = `On utilise la formule $\\\\dfrac{a^n}{b^n}=\\\\left(\\\\dfrac{a}{b}\\\\right)^{n}$ avec\n        $a=${a}$,  $b=${b}$ et $n=${n}$.<br>\n        $\\\\dfrac{${ecritureParentheseSiNegatif(a)}^{${n}}}{${ecritureParentheseSiNegatif(b)}^{${n}}}=\\\\left(\\\\dfrac{${ecritureParentheseSiNegatif(a)}}{${ecritureParentheseSiNegatif(b)}}\\\\right)^{${n}}=${miseEnEvidence(`${s}^{${n}}`)}$\n        `\n        this.reponse = `${s}^{${n}}`\n        break\n    }\n    this.canEnonce = this.question// 'Compléter'\n    this.canReponseACompleter = ''\n  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