{"version":3,"file":"2N32-1-O2Jfh4XR.js","sources":["../../src/exercices/2e/2N32-1.js"],"sourcesContent":["import { combinaisonListes } from '../../lib/outils/arrayOutils'\nimport Exercice from '../deprecatedExercice.js'\nimport { texteGras } from '../../lib/format/style'\nimport { listeQuestionsToContenu, randint } from '../../modules/outils.js'\nimport { ajouteChampTexteMathLive } from '../../lib/interactif/questionMathLive.js'\nimport { setReponse } from '../../lib/interactif/gestionInteractif.js'\nexport const titre = 'Justify the existence of a square root'\nexport const interactifReady = true\nexport const interactifType = 'mathLive'\nexport const dateDeModifImportante = '15/11/2023'\n/**\n * 2N32-1, ex 2N10\n * @author Stéphane Guyon et Gilles Mora (interactif + modif correction)\n */\nexport const uuid = '55cc0'\nexport const ref = '2N32-1'\nexport default function ExistenceDUneRacineCarree () {\n  Exercice.call(this) // Héritage de la classe Exercice()\n  this.titre = titre\n\n  this.nbQuestions = 5\n  this.nbCols = 2\n  this.nbColsCorr = 2\n  this.sup = 1 //\n  this.correctionDetaillee = true\n  this.correctionDetailleeDisponible = true\n  this.nouvelleVersion = function () {\n    if (!this.interactif) {\n      this.consigne = ' Does the proposed number exist? Justify.'\n    } else {\n      this.consigne = 'Does the proposed number exist? <br>Answer Yes or No.'\n    }\n    this.listeQuestions = [] // Liste de questions\n    this.listeCorrections = [] // Liste de questions corrigées\n    const typesDeQuestionsDisponibles = [1, 2, 3, 4, 5, 6, 7, 8]; let typesDeQuestions//,\n    const listeTypeDeQuestions = combinaisonListes(typesDeQuestionsDisponibles, this.nbQuestions)\n    let a; let b; let c; let d; let e; let f; let g; let h; let j; let k = 0\n    for (let i = 0, texte, texteCorr, reponse, corr, cpt = 0; i < this.nbQuestions && cpt < 50;) {\n      typesDeQuestions = listeTypeDeQuestions[i]\n      const corrDetail = `${texteGras('Definition')}: $\\\\sqrt{a}$ is the positive number whose square is $a$.<br>It therefore checks $\\\\sqrt{a}\\\\times \\\\sqrt{a}=a$. <br>As $a$ is a square, it is a positive number.<br>So, the square root of a negative number does not exist. <br><br>${texteGras('Method')}: To show that a square root exists, simply show that the number under the radical is positive. <br><br>`\n\n      switch (typesDeQuestions) {\n        // Case by case, we define the type of numbers we want\n        // How many digits? What values?\n        case 1:\n          a = randint(2, 9)\n          corr = `Since $\\\\sqrt{${a}} \\\\geqslant 0$, then $\\\\sqrt{\\\\sqrt{${a}}}$ exists. `\n          texte = `$\\\\sqrt{\\\\sqrt{${a}}}$`\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          reponse = ['Yes', 'Yes', 'YES']\n\n          break\n        case 2:\n          b = randint(2, 9) * (-1)\n          texte = `$\\\\sqrt{${b}}$`\n          reponse = ['No', 'No', 'NO']\n          corr = `$${b}$ is a negative number so $\\\\sqrt{${b}}$ does not exist. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          break\n        case 3:\n          c = randint(2, 9) * (-1)\n          d = c * c\n          texte = `$\\\\sqrt{\\\\left(${c}\\\\right)^{2}}$`\n          reponse = ['Yes', 'Yes', 'YES']\n          corr = `We have $\\\\left(${c}\\\\right)^{2}=\\\\left(${c}\\\\right)\\\\times \\\\left(${c}\\\\right)=${d}$. <br>As $${d}$ is a positive number, $\\\\sqrt{\\\\left(${c}\\\\right)^{2}}$ exists. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n\n          break\n        case 4:\n          e = randint(2, 9)\n          texte = `$-\\\\sqrt{${e}}$`\n          reponse = ['Yes', 'Yes', 'YES']\n          corr = `${e} is a positive number so $-\\\\sqrt{${e}}$ exists.<br>${texteGras('Noticed')}: The sign $-$ being placed in front of the radical symbol, the number $-\\\\sqrt{${e}}$ is therefore negative. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          break\n        case 5:\n          f = randint(2, 9) * (-1)\n          g = f * f\n          texte = `$\\\\sqrt{-\\\\left(${f}\\\\right)^{2}}$`\n          reponse = ['No', 'No', 'NO']\n          corr = `We have $-\\\\left(${f}\\\\right)^{2}=-\\\\left(${f}\\\\right)\\\\times \\\\left(${f}\\\\right)=-${g}$.<br>Like $ -${g}$ is a negative number, $\\\\sqrt{-\\\\left(${f}\\\\right)^{2}}$ does not exist. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          break\n        case 6:\n          h = randint(2, 3)\n          texte = `$\\\\sqrt{${h}-\\\\pi}$`\n          reponse = ['No', 'No', 'NO']\n          corr = `Since $\\\\pi>3$ then $${h}-\\\\pi$ is a negative number. <br>Thus, $\\\\sqrt{${h}-\\\\pi}$ does not exist. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          break\n\n        case 7:\n          k = randint(4, 8)\n          texte = `$\\\\sqrt{${k}-\\\\pi}$`\n          reponse = ['Yes', 'Yes', 'YES']\n          corr = `Since $\\\\pi\\\\approx 3.14$ then $${k}-\\\\pi$ is a positive number.<br>Thus, $\\\\sqrt{${k}-\\\\pi}$ exists. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          break\n\n        case 8:\n          j = randint(2, 12)\n          texte = `$\\\\sqrt{-${j}^{2}}$`\n          reponse = ['No', 'No', 'NO']\n          corr = `We have $-${j}^{2}=-${j}\\\\times ${j}=-${j * j}$. <br>As $-${j * j}$ is a negative real, $\\\\sqrt{-${j}^{2}}$ does not exist. `\n          if (this.correctionDetaillee) {\n            texteCorr = corrDetail\n            texteCorr += corr\n          } else {\n            texteCorr = corr\n          }\n          break\n      }\n      setReponse(this, i, reponse, { formatInteractif: 'text' })\n      if (this.interactif) {\n        texte += ajouteChampTexteMathLive(this, i, 'largeur01 inline')\n      }\n      if (this.listeQuestions.indexOf(texte) === -1) { // Si la question n'a jamais été posée, on en créé une autre\n        this.listeQuestions.push(texte)\n        this.listeCorrections.push(texteCorr)\n        i++\n      }\n      cpt++\n    }\n    listeQuestionsToContenu(this)\n  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